3x^2-(2x-4)=3+3x^2+1

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Solution for 3x^2-(2x-4)=3+3x^2+1 equation: 


Simplifying
3x2 + -1(2x + -4) = 3 + 3x2 + 1

Reorder the terms:
3x2 + -1(-4 + 2x) = 3 + 3x2 + 1
3x2 + (-4 * -1 + 2x * -1) = 3 + 3x2 + 1
3x2 + (4 + -2x) = 3 + 3x2 + 1

Reorder the terms:
4 + -2x + 3x2 = 3 + 3x2 + 1

Reorder the terms:
4 + -2x + 3x2 = 3 + 1 + 3x2

Combine like terms: 3 + 1 = 4
4 + -2x + 3x2 = 4 + 3x2

Add '-4' to each side of the equation.
4 + -2x + -4 + 3x2 = 4 + -4 + 3x2

Reorder the terms:
4 + -4 + -2x + 3x2 = 4 + -4 + 3x2

Combine like terms: 4 + -4 = 0
0 + -2x + 3x2 = 4 + -4 + 3x2
-2x + 3x2 = 4 + -4 + 3x2

Combine like terms: 4 + -4 = 0
-2x + 3x2 = 0 + 3x2
-2x + 3x2 = 3x2

Add '-3x2' to each side of the equation.
-2x + 3x2 + -3x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-2x + 0 = 3x2 + -3x2
-2x = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-2x = 0

Solving
-2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-2'.
x = 0

Simplifying
x = 0

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